Apples are sold at Rs` 48 4/5` per kg. What is the cost of `3 3/4` kg of apples?

Answer

To find the cost of \(3 \frac{3}{4}\) kg of apples when the price per kg is \(48 \frac{4}{5}\), we will follow these steps:

### Step 1: Convert the mixed numbers to improper fractions.
1. **Convert \(48 \frac{4}{5}\)**:
\[ 48 \frac{4}{5} = \frac{(48 \times 5) + 4}{5} = \frac{240 + 4}{5} = \frac{244}{5} \]

2. **Convert \(3 \frac{3}{4}\)**:
\[ 3 \frac{3}{4} = \frac{(3 \times 4) + 3}{4} = \frac{12 + 3}{4} = \frac{15}{4} \]

### Step 2: Calculate the total cost.
Now, we will multiply the price per kg by the weight of apples in kg:
\[ \text{Cost} = \text{Price per kg} \times \text{Weight in kg} \]
\[ \text{Cost} = \frac{244}{5} \times \frac{15}{4} \]

### Step 3: Multiply the fractions.
To multiply the fractions, we multiply the numerators and the denominators:
\[ \text{Cost} = \frac{244 \times 15}{5 \times 4} \]
Calculating the numerator:
\[ 244 \times 15 = 3660 \]
Calculating the denominator:
\[ 5 \times 4 = 20 \]
So we have:
\[ \text{Cost} = \frac{3660}{20} \]

### Step 4: Simplify the fraction.
Now, we simplify \(\frac{3660}{20}\):
\[ \frac{3660 \div 20}{20 \div 20} = \frac{183}{1} = 183 \]

### Final Answer:
The cost of \(3 \frac{3}{4}\) kg of apples is Rs. 183.

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