Fill in the blanks
Q`41 2/3xx18 3/5`

Answer

To solve the problem \( 41 \frac{2}{3} \times 18 \frac{3}{5} \), we will follow these steps:

### Step 1: Convert Mixed Numbers to Improper Fractions
First, we need to convert the mixed numbers into improper fractions.

For \( 41 \frac{2}{3} \):
\[ 41 \frac{2}{3} = \frac{(41 \times 3) + 2}{3} = \frac{123 + 2}{3} = \frac{125}{3} \]

For \( 18 \frac{3}{5} \):
\[ 18 \frac{3}{5} = \frac{(18 \times 5) + 3}{5} = \frac{90 + 3}{5} = \frac{93}{5} \]

### Step 2: Multiply the Improper Fractions
Now that we have both numbers as improper fractions, we can multiply them:
\[ \frac{125}{3} \times \frac{93}{5} = \frac{125 \times 93}{3 \times 5} \]

### Step 3: Calculate the Numerator and Denominator
Now we calculate the numerator and the denominator:
\[ 125 \times 93 = 11625 \]
\[ 3 \times 5 = 15 \]
So, we have:
\[ \frac{11625}{15} \]

### Step 4: Simplify the Fraction
Next, we simplify \( \frac{11625}{15} \):
\[ 11625 \div 15 = 775 \]

### Final Answer
Thus, the value of \( 41 \frac{2}{3} \times 18 \frac{3}{5} \) is \( 775 \).

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