Each bag of cement weighs 48.5 kg. How many such bags will weigh 2231 kg?

Options

A. 44
B. 46
C. 48
D. 50

Answer

To solve the problem of how many bags of cement weighing 48.5 kg each are needed to equal a total weight of 2231 kg, we can follow these steps:

### Step-by-Step Solution:

1. **Identify the weights**:
- Weight of each bag of cement = 48.5 kg
- Total weight to be achieved = 2231 kg

2. **Set up the equation**:
- To find the number of bags, we need to divide the total weight by the weight of each bag.
- The equation will be:
\[ \text{Number of bags} = \frac{\text{Total weight}}{\text{Weight of each bag}} = \frac{2231 \text{ kg}}{48.5 \text{ kg}} \]

3. **Eliminate the decimal**:
- To simplify the division, we can multiply both the numerator and the denominator by 10 to remove the decimal point from the denominator.
- This gives us:
\[ \frac{2231 \times 10}{48.5 \times 10} = \frac{22310}{485} \]

4. **Perform the division**:
- Now we divide 22310 by 485.
- Performing the division:
\[ 22310 \div 485 \approx 46 \]

5. **Conclusion**:
- Therefore, the number of bags needed is approximately 46 bags.

### Final Answer:
The number of bags of cement required is **46 bags**.