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Solve the following eqations.Check your ...

Solve the following eqations.Check your result in each case
`2X-1/3=1/5-X`

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To solve the equation \(2x - \frac{1}{3} = \frac{1}{5} - x\), we will follow these steps: ### Step 1: Rearranging the Equation We want to get all terms involving \(x\) on one side and constant terms on the other side. Let's add \(x\) to both sides of the equation. \[ 2x + x - \frac{1}{3} = \frac{1}{5} \] This simplifies to: \[ 3x - \frac{1}{3} = \frac{1}{5} \] **Hint:** To isolate \(x\), you can move the \(x\) terms to one side and the constant terms to the other side. ### Step 2: Adding \(\frac{1}{3}\) to Both Sides Next, we will add \(\frac{1}{3}\) to both sides to eliminate the constant term on the left side. \[ 3x = \frac{1}{5} + \frac{1}{3} \] **Hint:** When adding fractions, make sure to find a common denominator. ### Step 3: Finding a Common Denominator The least common multiple of 5 and 3 is 15. We will convert both fractions to have a denominator of 15. \[ \frac{1}{5} = \frac{3}{15} \quad \text{and} \quad \frac{1}{3} = \frac{5}{15} \] So we can rewrite the equation as: \[ 3x = \frac{3}{15} + \frac{5}{15} \] **Hint:** Always convert fractions to the same denominator before adding them. ### Step 4: Adding the Fractions Now, we can add the fractions on the right side: \[ 3x = \frac{3 + 5}{15} = \frac{8}{15} \] **Hint:** Combine the numerators while keeping the denominator the same. ### Step 5: Solving for \(x\) Now, we divide both sides by 3 to solve for \(x\): \[ x = \frac{8}{15} \div 3 = \frac{8}{15} \times \frac{1}{3} = \frac{8}{45} \] **Hint:** Dividing by a number is the same as multiplying by its reciprocal. ### Step 6: Checking the Result To verify our solution, we will substitute \(x = \frac{8}{45}\) back into the original equation: Left Side: \[ 2x - \frac{1}{3} = 2 \times \frac{8}{45} - \frac{1}{3} = \frac{16}{45} - \frac{1}{3} \] Convert \(\frac{1}{3}\) to have a denominator of 45: \[ \frac{1}{3} = \frac{15}{45} \] So, \[ \frac{16}{45} - \frac{15}{45} = \frac{1}{45} \] Right Side: \[ \frac{1}{5} - x = \frac{1}{5} - \frac{8}{45} \] Convert \(\frac{1}{5}\) to have a denominator of 45: \[ \frac{1}{5} = \frac{9}{45} \] So, \[ \frac{9}{45} - \frac{8}{45} = \frac{1}{45} \] Since both sides are equal, the solution is verified. **Final Answer:** \[ x = \frac{8}{45} \]
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RS AGGARWAL-LINEAR EQUATION IN ONE VARIABLE-EXERCISE 7A
  1. Solve the following eqations.Check your result in each case 2(X-2)+3(4...

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  2. Solve the following equations.Check your result in each case 5(2X-3)-3...

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  3. Solve the following eqations.Check your result in each case 2X-1/3=1/5...

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  4. Solve the following equations.Check your result in each case 1/2X-3=5+...

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  5. Solve the following equations.Check your result in each case x/2+x/4=1...

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  6. Solve the following equations.Check your result in each case 3x+2(x+2)...

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  7. Solve the following equations.Check your result in each case 13(y-4)-3...

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  8. Solve the following eqations.Check your result in each case (2m+5)=3m-...

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  9. Solve the following eqations.Check your result in each case 6(3x+2)-5(...

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  10. Solve the following equations.Check your result in each case t-(2t+5)-...

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  11. Solve the following equations.Check your result in each case 2/3x=3/8x...

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  12. Solve the following equations.Check your result in each case (3x-1)/5-...

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  13. Solve the following eqations.Check your result in each case 2x-3=3/10(...

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  14. Solve the following equations. (y-1)/3-(y-2)/4=1

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  15. Solve the following equation.Check your result in each case (x-2)/4+1/...

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  16. Solve the following equations.Check your result in each case (2x-1)/3-...

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  17. Solve the following equations.Check your result in each case (y+7)/3=1...

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  18. Solve the following equation.Check your result in each case 2/7(x-9)+x...

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  19. Solve the following equation.Check your result in each case (2x-3)/5+(...

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  20. Solve the following equation.Check your result in each case 3/4(7x-1)-...

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