A number when multiplied by 4, exceeds itself by 45. find the number.

Options

A. 11
B. 12
C. 13
D. 15

Answer

To solve the problem step by step, let's denote the unknown number as \( x \).

### Step 1: Set up the equation
According to the problem, when the number \( x \) is multiplied by 4, it exceeds the number itself by 45. This can be expressed mathematically as:
\[ 4x = x + 45 \]

### Step 2: Rearrange the equation
To solve for \( x \), we need to rearrange the equation by moving all terms involving \( x \) to one side. We can subtract \( x \) from both sides:
\[ 4x - x = 45 \]

### Step 3: Simplify the equation
Now, simplify the left side:
\[ 3x = 45 \]

### Step 4: Solve for \( x \)
Next, we divide both sides of the equation by 3 to isolate \( x \):
\[ x = \frac{45}{3} \]
\[ x = 15 \]

### Conclusion
The number we are looking for is \( 15 \).

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