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A labourer is engaged for 20 days on the...

A labourer is engaged for 20 days on the condition that he will receive ₹120 for each day he works and will be fined ₹10 for each day he is absent. If he receive 1880 in all, for how many days did he remains absent?

A

2 days

B

12 days

C

10 days

D

4 days

Text Solution

AI Generated Solution

The correct Answer is:
To solve the problem, we need to determine how many days the laborer was absent based on the information provided. ### Step-by-step Solution: 1. **Define Variables**: Let \( x \) be the number of days the laborer worked. Since he was engaged for 20 days, the number of days he was absent will be \( 20 - x \). 2. **Calculate Earnings**: The laborer earns ₹120 for each day he works. Therefore, his total earnings from working \( x \) days will be: \[ \text{Earnings from work} = 120x \] 3. **Calculate Fines**: The laborer is fined ₹10 for each day he is absent. Thus, the total fines for \( 20 - x \) days of absence will be: \[ \text{Fines for absence} = 10(20 - x) = 200 - 10x \] 4. **Set Up the Equation**: According to the problem, the total amount received by the laborer after working and being fined is ₹1880. Therefore, we can set up the equation: \[ \text{Total Earnings} - \text{Total Fines} = 1880 \] Substituting the expressions we found: \[ 120x - (200 - 10x) = 1880 \] 5. **Simplify the Equation**: Simplifying the equation gives: \[ 120x - 200 + 10x = 1880 \] Combine like terms: \[ 130x - 200 = 1880 \] 6. **Isolate \( x \)**: Add 200 to both sides: \[ 130x = 1880 + 200 \] \[ 130x = 2080 \] 7. **Solve for \( x \)**: Divide both sides by 130: \[ x = \frac{2080}{130} \] \[ x = 16 \] 8. **Calculate Days Absent**: Since \( x = 16 \), the number of days the laborer was absent is: \[ 20 - x = 20 - 16 = 4 \] ### Final Answer: The laborer was absent for **4 days**.
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RS AGGARWAL-LINEAR EQUATION IN ONE VARIABLE-EXERCISE 7 B
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