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Hari babu left one-third of his property...

Hari babu left one-third of his property to his son, one-fourth to his daughter and the remainder to his wife.If his wife share is 18000, What was the worth of his total property?

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To solve the problem step by step, we can follow these instructions: ### Step 1: Define the total property Let the total worth of Hari Babu's property be represented as \( x \). ### Step 2: Determine shares for son and daughter According to the problem: - The son receives \( \frac{1}{3} \) of the total property, which is \( \frac{1}{3}x \). - The daughter receives \( \frac{1}{4} \) of the total property, which is \( \frac{1}{4}x \). ### Step 3: Calculate the remainder for the wife The remainder of the property, which goes to the wife, can be calculated as follows: \[ \text{Wife's share} = x - \left(\frac{1}{3}x + \frac{1}{4}x\right) \] ### Step 4: Find a common denominator To simplify the expression, we need to find a common denominator for \( \frac{1}{3} \) and \( \frac{1}{4} \). The least common multiple (LCM) of 3 and 4 is 12. Thus, we can rewrite the fractions: \[ \frac{1}{3}x = \frac{4}{12}x \quad \text{and} \quad \frac{1}{4}x = \frac{3}{12}x \] ### Step 5: Substitute back into the equation Now, substituting these values back into the equation for the wife's share: \[ \text{Wife's share} = x - \left(\frac{4}{12}x + \frac{3}{12}x\right) = x - \frac{7}{12}x \] This simplifies to: \[ \text{Wife's share} = \frac{5}{12}x \] ### Step 6: Set up the equation We know from the problem that the wife's share is \( 18,000 \): \[ \frac{5}{12}x = 18,000 \] ### Step 7: Solve for \( x \) To find \( x \), we can multiply both sides by \( \frac{12}{5} \): \[ x = 18,000 \times \frac{12}{5} \] ### Step 8: Calculate the total property value Calculating the right side: \[ x = 18,000 \times 2.4 = 43,200 \] ### Conclusion The total worth of Hari Babu's property is \( 43,200 \). ---
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RS AGGARWAL-LINEAR EQUATION IN ONE VARIABLE-EXERCISE 7 B
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