in an election there were two cadidates A and B the total number of voters in this constituency was 60000 and 80% of the total votes were polled if 60% of the polled votes were cast in favour of A how many votes were reccived by B?

Options

A. 19100
B. 20000
C. 21000
D. 19200

Answer

To solve the problem step by step, we will follow these calculations:

### Step 1: Calculate the total number of votes polled
The total number of voters is given as 60,000, and 80% of these votes were polled.

\[ \text{Votes polled} = 80\% \text{ of } 60,000 = \frac{80}{100} \times 60,000 = 48,000 \]

### Step 2: Calculate the number of votes received by candidate A
It is given that 60% of the polled votes were cast in favor of candidate A.

\[ \text{Votes for A} = 60\% \text{ of } 48,000 = \frac{60}{100} \times 48,000 = 28,800 \]

### Step 3: Calculate the number of votes received by candidate B
Since there are only two candidates, the votes received by candidate B can be calculated by subtracting the votes received by candidate A from the total votes polled.

\[ \text{Votes for B} = \text{Total votes polled} - \text{Votes for A} = 48,000 - 28,800 = 19,200 \]

### Final Answer
Candidate B received **19,200 votes**.

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