The population of a town increases at 5% per annum . Its present population is 16000. what will ne its population after 2 years?

Answer

To find the population of the town after 2 years with an annual increase of 5%, we can follow these steps:

### Step 1: Calculate the increase for the first year.
- **Current Population**: 16,000
- **Percentage Increase**: 5%

To find the increase:
\[ \text{Increase} = \text{Current Population} \times \frac{\text{Percentage Increase}}{100} \]
\[ \text{Increase} = 16000 \times \frac{5}{100} = 16000 \times 0.05 = 800 \]

### Step 2: Calculate the population after the first year.
- **Population after 1st Year**:
\[ \text{Population after 1st Year} = \text{Current Population} + \text{Increase} \]
\[ \text{Population after 1st Year} = 16000 + 800 = 16800 \]

### Step 3: Calculate the increase for the second year.
- **New Current Population**: 16,800

To find the increase for the second year:
\[ \text{Increase} = 16800 \times \frac{5}{100} = 16800 \times 0.05 = 840 \]

### Step 4: Calculate the population after the second year.
- **Population after 2nd Year**:
\[ \text{Population after 2nd Year} = \text{New Current Population} + \text{Increase} \]
\[ \text{Population after 2nd Year} = 16800 + 840 = 17640 \]

### Final Answer:
The population of the town after 2 years will be **17,640**.

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