Home
Class 7
MATHS
In the given figure, side BC of /\ ABC i...

In the given figure, side BC of `/_\ ABC` is produced to D and CE||BA. If `/_BAC = 50^(@)`,then `/_ACE` = ……

Text Solution

AI Generated Solution

The correct Answer is:
To solve the problem step by step, we will use the properties of parallel lines and angles. ### Step-by-Step Solution: 1. **Identify the Given Information:** - We are given that angle \( \angle BAC = 50^\circ \). - Line segment \( CE \) is parallel to line segment \( AB \). - Line segment \( BC \) is extended to point \( D \). 2. **Understand the Relationship Between Angles:** - Since \( CE \) is parallel to \( AB \) and \( AC \) acts as a transversal line, we can apply the properties of alternate interior angles. 3. **Apply the Alternate Interior Angles Theorem:** - According to the Alternate Interior Angles Theorem, if two parallel lines are cut by a transversal, then the alternate interior angles are equal. - Therefore, \( \angle BAC \) (which is \( 50^\circ \)) is equal to \( \angle ACE \). 4. **Conclude the Value of Angle \( ACE \):** - Since \( \angle BAC = 50^\circ \), we can conclude that: \[ \angle ACE = \angle BAC = 50^\circ \] ### Final Answer: \[ \angle ACE = 50^\circ \]
Promotional Banner

Topper's Solved these Questions

  • CONSTRUCTIONS

    RS AGGARWAL|Exercise TEST PAPER (True/False)|4 Videos
  • CONSTRUCTIONS

    RS AGGARWAL|Exercise TEST PAPER (M.C.Q)|7 Videos
  • CONGRUENCE

    RS AGGARWAL|Exercise EXERCISE|18 Videos
  • DECIMALS

    RS AGGARWAL|Exercise TEST PAPER-3(D)|5 Videos

Similar Questions

Explore conceptually related problems

In the given figure, side BC of /_ ABC is produced to D such that /_ ABC = 70^(@) , and /_ ACD = 120^(@) . Then, /_ BAC = ?

In the given figure,O is the centre of the circle and BA =AC. If /_ABC=50^(@), find /_BOC and /_BDC.

The side AC of a triangle ABC is produced to D such that BC=CD . If /_ACB is 70^(@) , then what is /_ADB equal to ?

In the given figure, side BC of Delta ABC is bisected at D and O is any point AD.BO and CO produced meet AC and AB at E and F respectively, and AD is respectively, and AD is produced to X so that D is the midpoint of OX. Prove that AO:AX=AF:AB and show that EF||BC .

In Figure,side BC of ABC is produced to point D such that bisetors of /_ABC and /_ACD meet at a point E* If /_BAC=68^(@), find /_BEC

In the given figure, ABC is a triangle in which BC is produced to D. If angle A : angle B : angle C :: 3 : 2 : 1 and AC bot CE , then angle ECD is :