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The circumferences of two circles are in...

The circumferences of two circles are in the ratio 3:4. Find the ratio of their areas.

A

`9:16`

B

`16:9`

C

`6:9`

D

`9:6`

Text Solution

AI Generated Solution

The correct Answer is:
To find the ratio of the areas of two circles given the ratio of their circumferences, we can follow these steps: ### Step 1: Understand the relationship between circumference and radius. The circumference \( C \) of a circle is given by the formula: \[ C = 2\pi r \] where \( r \) is the radius of the circle. ### Step 2: Set up the ratio of the circumferences. Given that the circumferences of the two circles are in the ratio \( 3:4 \), we can express this as: \[ \frac{C_1}{C_2} = \frac{3}{4} \] Let \( C_1 = 2\pi r_1 \) and \( C_2 = 2\pi r_2 \), where \( r_1 \) and \( r_2 \) are the radii of the first and second circles, respectively. ### Step 3: Substitute the circumference formulas into the ratio. Substituting the formulas for circumference into the ratio gives us: \[ \frac{2\pi r_1}{2\pi r_2} = \frac{3}{4} \] The \( 2\pi \) cancels out: \[ \frac{r_1}{r_2} = \frac{3}{4} \] ### Step 4: Find the ratio of the radii. From the above step, we have: \[ r_1 : r_2 = 3 : 4 \] ### Step 5: Find the ratio of the areas. The area \( A \) of a circle is given by the formula: \[ A = \pi r^2 \] Thus, the areas of the two circles can be expressed as: \[ A_1 = \pi r_1^2 \quad \text{and} \quad A_2 = \pi r_2^2 \] Now, we can find the ratio of the areas: \[ \frac{A_1}{A_2} = \frac{\pi r_1^2}{\pi r_2^2} = \frac{r_1^2}{r_2^2} \] ### Step 6: Substitute the ratio of the radii into the area ratio. We already found that \( \frac{r_1}{r_2} = \frac{3}{4} \). Therefore: \[ \frac{r_1^2}{r_2^2} = \left(\frac{3}{4}\right)^2 = \frac{9}{16} \] ### Conclusion: State the final ratio of the areas. Thus, the ratio of the areas of the two circles is: \[ A_1 : A_2 = 9 : 16 \] ---
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