Home
Class 7
MATHS
Each side of a square park is 80 m. At e...

 Each side of a square park is 80 m. At each corner of the park there is a flower bed in the form of a quadrant of a circle of radius 14 m, as shown in the figure. Find the area of the remaining part of the park.

Text Solution

AI Generated Solution

The correct Answer is:
To solve the problem step by step, we will calculate the area of the square park and then subtract the area of the flower beds (quadrants of circles) from it. ### Step 1: Calculate the area of the square park The formula for the area of a square is: \[ \text{Area} = \text{side}^2 \] Given that each side of the square park is 80 m: \[ \text{Area} = 80 \times 80 = 6400 \, \text{m}^2 \] ### Step 2: Calculate the area of one quadrant of a circle The formula for the area of a full circle is: \[ \text{Area} = \pi r^2 \] Since we have a quadrant (which is one-fourth of a circle), the area of one quadrant is: \[ \text{Area of one quadrant} = \frac{1}{4} \pi r^2 \] Given that the radius \( r \) is 14 m: \[ \text{Area of one quadrant} = \frac{1}{4} \times \frac{22}{7} \times (14)^2 \] Calculating \( (14)^2 \): \[ (14)^2 = 196 \] Now substituting this into the equation: \[ \text{Area of one quadrant} = \frac{1}{4} \times \frac{22}{7} \times 196 \] Calculating further: \[ = \frac{22 \times 196}{4 \times 7} \] \[ = \frac{22 \times 196}{28} \] Now simplifying \( \frac{196}{28} = 7 \): \[ = 22 \times 7 = 154 \, \text{m}^2 \] ### Step 3: Calculate the area of four quadrants Since there are four corners, we multiply the area of one quadrant by 4: \[ \text{Area of four quadrants} = 4 \times 154 = 616 \, \text{m}^2 \] ### Step 4: Calculate the area of the remaining part of the park To find the area of the remaining part of the park, we subtract the area of the flower beds from the area of the square park: \[ \text{Area of remaining part} = \text{Area of square} - \text{Area of four quadrants} \] \[ = 6400 - 616 = 5784 \, \text{m}^2 \] ### Final Answer The area of the remaining part of the park is: \[ \boxed{5784 \, \text{m}^2} \]
Promotional Banner

Topper's Solved these Questions

  • MENSURATION

    RS AGGARWAL|Exercise EXERCISE 20A|20 Videos
  • MENSURATION

    RS AGGARWAL|Exercise EXERCISE 20B|16 Videos
  • LINES AND ANGLES

    RS AGGARWAL|Exercise Exercise 13|11 Videos
  • PERCENTAGE

    RS AGGARWAL|Exercise TEST PAPER|16 Videos

Similar Questions

Explore conceptually related problems

A square park has each side 50 m. At each corner of the park, there is a flower bed in the form of a quadrant of radius 7 m, as shown in the figure. Find the area of remaining part of the park.

A square park has each side of 100 m. At each corner of the park, there is a flower bed in the form of a quadrant of radius 14 m as shown in Fig. 15.37. Find the area of the remaining part of the park (U s e pi=22//7) . (FIGURE)

The side of a square park is 100 m. Perimeter of the park is:

In each of the corners, there is a flower bed in the form of a quadrant of a circle of radius 2 m. Also, there is a flower bed in the form of a circle of radius 2 m in the middle of the plot. Find the area of the remaining plot.

From each corner of a square of side 4cm a quadrant of a circle of radius 1cm is cut and also a circle of diameter 2cm is cut as shown in Fig.12.23. Find the area of the remaining portion of the square.

Five square flower beds each of sides 1m are dug on a piece of land 5m long and 4m wide. What is the area of the remaining part of the land?

Five square flower beds each of sides 1.2 m are dug on a piece of land 4.8 m long and 4.2 m wide. What is the area of the remaining part of the land ?

From a square of side 8 cm, two quadrants of a circle of radii 1.4 cm are cut from two corners. Another circle of radius 4.2 cm is also cut from the centre as shown in the figure. Find the area of the remaining (shaded) portion of the square. [Take pi =22/7 ]

From a square of side 8 cm, two quadrants of a circle of radii 1.4 cm are cut from two corners . Another circle of radius 4.2 cm is also cut from the centre as shown in the figure . Find the area of the remaining (shaded) portion of the square . ["Take"pi=(22)/(7)]

A park is in the form of a circle with radius 35m. At the centre of the park, there is a lawn in the form of a square. If the area of the park, excluding the lawn is 2500 m^(2) find the cost of levelling the lawn at the rate of Rs 50 per m^(2)