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Find the area of a rhombus in which Q(i)...

 Find the area of a rhombus in which
Q(i) each side = 2 dm and height = 12.6 cm.
(ii) 8 dm 5 cm and 5 dm 6 cm.

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The correct Answer is:
To solve the problem of finding the area of a rhombus for the two given cases, we will follow these steps: ### Part (i): Each side = 2 dm and height = 12.6 cm 1. **Convert the side length from decimeters to centimeters**: - Given side length = 2 dm - Conversion: 1 dm = 10 cm - Therefore, \( 2 \, \text{dm} = 2 \times 10 = 20 \, \text{cm} \) 2. **Use the formula for the area of a rhombus**: - The formula for the area of a rhombus is: \[ \text{Area} = \text{Base} \times \text{Height} \] - Here, the base (side length) is 20 cm and the height is 12.6 cm. 3. **Calculate the area**: - Substitute the values into the formula: \[ \text{Area} = 20 \, \text{cm} \times 12.6 \, \text{cm} \] - Perform the multiplication: \[ \text{Area} = 252 \, \text{cm}^2 \] ### Part (ii): Base = 8 dm 5 cm and height = 5 dm 6 cm 1. **Convert the base and height from mixed units to centimeters**: - For the base: - Given base = 8 dm 5 cm - Conversion: \( 8 \, \text{dm} = 8 \times 10 = 80 \, \text{cm} \) - Therefore, \( \text{Base} = 80 \, \text{cm} + 5 \, \text{cm} = 85 \, \text{cm} \) - For the height: - Given height = 5 dm 6 cm - Conversion: \( 5 \, \text{dm} = 5 \times 10 = 50 \, \text{cm} \) - Therefore, \( \text{Height} = 50 \, \text{cm} + 6 \, \text{cm} = 56 \, \text{cm} \) 2. **Use the formula for the area of a rhombus**: - Substitute the values into the area formula: \[ \text{Area} = \text{Base} \times \text{Height} = 85 \, \text{cm} \times 56 \, \text{cm} \] 3. **Calculate the area**: - Perform the multiplication: \[ \text{Area} = 4760 \, \text{cm}^2 \] ### Final Answers: - Part (i): The area of the rhombus is \( 252 \, \text{cm}^2 \). - Part (ii): The area of the rhombus is \( 4760 \, \text{cm}^2 \).
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