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The base of a triangular field is three ...

 The base of a triangular field is three times its height. If the cost of cultivating the field at Rs.1080 per hectare is Rs.14580, find its base and height.

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To solve the problem step by step, we will find the base and height of the triangular field given the conditions in the question. ### Step 1: Define Variables Let the height of the triangular field be \( h \) meters. According to the problem, the base \( b \) is three times the height. Therefore, we can express the base as: \[ b = 3h \] ### Step 2: Calculate the Area of the Triangle The area \( A \) of a triangle is given by the formula: \[ A = \frac{1}{2} \times \text{base} \times \text{height} \] Substituting the expressions for base and height, we get: \[ A = \frac{1}{2} \times (3h) \times h = \frac{3}{2} h^2 \] ### Step 3: Determine the Total Area from Cost We know the total cost of cultivating the field is Rs. 14,580, and the cost per hectare is Rs. 1,080. To find the area in hectares, we use the formula: \[ \text{Area in hectares} = \frac{\text{Total Cost}}{\text{Cost per hectare}} = \frac{14580}{1080} = 13.5 \text{ hectares} \] Now, converting hectares to square meters (1 hectare = 10,000 m²): \[ \text{Area in square meters} = 13.5 \times 10000 = 135000 \text{ m}^2 \] ### Step 4: Set Up the Equation Now we have two expressions for the area: 1. From the dimensions of the triangle: \( A = \frac{3}{2} h^2 \) 2. From the cost: \( A = 135000 \) Setting these equal gives: \[ \frac{3}{2} h^2 = 135000 \] ### Step 5: Solve for Height To isolate \( h^2 \), multiply both sides by \( \frac{2}{3} \): \[ h^2 = 135000 \times \frac{2}{3} = 90000 \] Now, take the square root of both sides to find \( h \): \[ h = \sqrt{90000} = 300 \text{ meters} \] ### Step 6: Calculate the Base Now that we have the height, we can find the base using the relationship \( b = 3h \): \[ b = 3 \times 300 = 900 \text{ meters} \] ### Conclusion The height of the triangular field is \( 300 \) meters and the base is \( 900 \) meters. ### Summary of Results - Height \( h = 300 \) meters - Base \( b = 900 \) meters
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RS AGGARWAL-MENSURATION-EXERCISE 20D
  1. Find the height of a triangular region having an area of 224 m^(2) and...

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  2. Find the base of a triangle whose area is 90cm^(2) and height 12 cm.

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  3. The base of a triangular field is three times its height. If the cost ...

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  4. The area of right triangular region is 129.5 cm^(2). If one of the sid...

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  5. Find the area of a right triangle whose base is 1.2 m and hypotenuse 3...

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  6. The legs of a right triangle are in the ratio 3 : 4 and its area is 10...

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  7. One side of a right-angled triangular scarf is 80 cm and its longest s...

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  8. Find the area of an equilateral triangle each of whose sides measures ...

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  9. The area of an equilateral triangle is (16 xx sqrt3) cm^(2). Find the ...

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  10. Find the length of the height of an equilateral triangle of side 24 cm...

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  11. Find the area of the triangle in which Q(i) a = 13 m, b=14 m, c=15 m,...

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  12. The lengths of the sides of a triangle are 33 cm, 44 cm and 55 cm resp...

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  13. The sides of a triangle are in the ratio 13:14: 15 and its perimeter i...

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  14. The sides of a triangle are 42 cm, 34 cm and 20 cm. Calculate its area...

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  15. The base of an isosceles triangle is 48 cm and one of its equal sides ...

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  16. The base of an isosceles triangle is 12 cm and its perimeter is 32 cm....

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  17. A diagonal of a quadrilateral is 26 cm and the perpendiculars drawn to...

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  18. In a quadrilateral ABCD, AB = 28 cm, BC = 26 cm, CD = 50 cm, DA = 40 c...

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  19. In the given figure, ABCD is a rectangle with length = 36 m and breadt...

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  20. In the given figure, ABCD is a rectangle in which AB = 40 cm and BC = ...

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