An aeroplane covers 1020 km in an hour. How much distance will it cover in `4(1)/(6)` hours?

Options

A. 4255 km
B. 4240 km
C. 4150 km
D. 4250 km

Answer

To solve the question of how much distance an aeroplane covers in \(4 \frac{1}{6}\) hours when it travels at a speed of 1020 km per hour, we can follow these steps:

### Step 1: Convert the mixed fraction into an improper fraction
The mixed fraction \(4 \frac{1}{6}\) can be converted into an improper fraction.

To convert:
1. Multiply the whole number (4) by the denominator (6): \(4 \times 6 = 24\).
2. Add the numerator (1) to this product: \(24 + 1 = 25\).
3. Place this result over the original denominator (6):

\[ 4 \frac{1}{6} = \frac{25}{6} \]

### Step 2: Use the formula for distance
The formula for distance is:

\[ \text{Distance} = \text{Speed} \times \text{Time} \]

Given:
- Speed = 1020 km/h
- Time = \(\frac{25}{6}\) hours

### Step 3: Substitute the values into the formula
Now, substitute the values into the distance formula:

\[ \text{Distance} = 1020 \times \frac{25}{6} \]

### Step 4: Calculate the distance
To calculate this, first divide 1020 by 6:

\[ 1020 \div 6 = 170 \]

Now multiply this result by 25:

\[ 170 \times 25 = 4250 \]

### Step 5: Write the final answer
Thus, the distance covered by the aeroplane in \(4 \frac{1}{6}\) hours is:

\[ \text{Distance} = 4250 \text{ km} \]