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The product of two rational numbers is (...

The product of two rational numbers is `(-28)/(81)`. If one of the numbers is `(14)/(27)` then the other one is

A

`(-2)/(3)`

B

`(2)/(3)`

C

`(3)/(2)`

D

`(-3)/(2)`

Text Solution

AI Generated Solution

The correct Answer is:
To find the other rational number when the product of two rational numbers is given, we can follow these steps: ### Step-by-Step Solution: 1. **Identify the Given Information**: We know that the product of two rational numbers is \(-\frac{28}{81}\). One of the numbers is \(\frac{14}{27}\). We need to find the other number, which we will denote as \(x\). 2. **Set Up the Equation**: Since the product of the two numbers is given, we can set up the equation: \[ \frac{14}{27} \times x = -\frac{28}{81} \] 3. **Isolate \(x\)**: To find \(x\), we need to isolate it. We can do this by dividing both sides of the equation by \(\frac{14}{27}\): \[ x = -\frac{28}{81} \div \frac{14}{27} \] 4. **Convert Division to Multiplication**: Dividing by a fraction is the same as multiplying by its reciprocal. Therefore, we can rewrite the equation as: \[ x = -\frac{28}{81} \times \frac{27}{14} \] 5. **Multiply the Fractions**: Now we multiply the fractions: \[ x = -\frac{28 \times 27}{81 \times 14} \] 6. **Simplify the Expression**: We can simplify the expression by canceling common factors: - The number \(27\) in the numerator and \(81\) in the denominator can be simplified: \[ 27 = 3 \times 9 \quad \text{and} \quad 81 = 9 \times 9 \quad \Rightarrow \quad \frac{27}{81} = \frac{1}{3} \] - The number \(28\) and \(14\) can also be simplified: \[ 28 = 2 \times 14 \quad \Rightarrow \quad \frac{28}{14} = 2 \] So, substituting these simplifications back into the equation gives us: \[ x = -\frac{2 \times 1}{3} = -\frac{2}{3} \] 7. **Final Answer**: Therefore, the other rational number is: \[ x = -\frac{2}{3} \]
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