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Evaluate root3(2744)....

Evaluate `root3(2744)`.

A

`13`

B

`14`

C

`15`

D

`16`

Text Solution

AI Generated Solution

The correct Answer is:
To evaluate the cube root of 2744, we can follow these steps: ### Step 1: Identify the number We need to find the cube root of 2744, which is denoted as \( \sqrt[3]{2744} \). **Hint:** Remember that the cube root of a number \( x \) is a number \( y \) such that \( y^3 = x \). ### Step 2: Factor the number We can try to factor 2744 to see if it can be expressed as a product of three identical factors. **Hint:** Start by checking if 2744 can be divided by small prime numbers like 2, 3, 5, etc. ### Step 3: Check divisibility by 2 Since 2744 is even, we can divide it by 2: - \( 2744 \div 2 = 1372 \) - \( 1372 \div 2 = 686 \) - \( 686 \div 2 = 343 \) So, we have \( 2744 = 2^3 \times 343 \). **Hint:** Keep dividing by 2 until you can no longer do so, then check the next smallest prime. ### Step 4: Factor 343 Now we need to factor 343. We can check if it is a perfect cube: - \( 7 \times 7 = 49 \) - \( 7 \times 49 = 343 \) Thus, \( 343 = 7^3 \). **Hint:** If you recognize a number as a perfect cube, it can simplify your calculations. ### Step 5: Combine the factors Now we can express 2744 as: \[ 2744 = 2^3 \times 7^3 \] **Hint:** Look for patterns in the factors that can help you simplify the expression. ### Step 6: Apply the cube root Now we can take the cube root of both sides: \[ \sqrt[3]{2744} = \sqrt[3]{2^3 \times 7^3} \] Using the property of cube roots, we can separate the factors: \[ \sqrt[3]{2^3} \times \sqrt[3]{7^3} = 2 \times 7 \] **Hint:** Remember that \( \sqrt[3]{a^3} = a \). ### Step 7: Calculate the final answer Now we can calculate: \[ 2 \times 7 = 14 \] So, the cube root of 2744 is: \[ \sqrt[3]{2744} = 14 \] ### Final Answer: The cube root of 2744 is **14**. ---
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