To evaluate the cube root of 2744, we can follow these steps:
### Step 1: Identify the number
We need to find the cube root of 2744, which is denoted as \( \sqrt[3]{2744} \).
**Hint:** Remember that the cube root of a number \( x \) is a number \( y \) such that \( y^3 = x \).
### Step 2: Factor the number
We can try to factor 2744 to see if it can be expressed as a product of three identical factors.
**Hint:** Start by checking if 2744 can be divided by small prime numbers like 2, 3, 5, etc.
### Step 3: Check divisibility by 2
Since 2744 is even, we can divide it by 2:
- \( 2744 \div 2 = 1372 \)
- \( 1372 \div 2 = 686 \)
- \( 686 \div 2 = 343 \)
So, we have \( 2744 = 2^3 \times 343 \).
**Hint:** Keep dividing by 2 until you can no longer do so, then check the next smallest prime.
### Step 4: Factor 343
Now we need to factor 343. We can check if it is a perfect cube:
- \( 7 \times 7 = 49 \)
- \( 7 \times 49 = 343 \)
Thus, \( 343 = 7^3 \).
**Hint:** If you recognize a number as a perfect cube, it can simplify your calculations.
### Step 5: Combine the factors
Now we can express 2744 as:
\[
2744 = 2^3 \times 7^3
\]
**Hint:** Look for patterns in the factors that can help you simplify the expression.
### Step 6: Apply the cube root
Now we can take the cube root of both sides:
\[
\sqrt[3]{2744} = \sqrt[3]{2^3 \times 7^3}
\]
Using the property of cube roots, we can separate the factors:
\[
\sqrt[3]{2^3} \times \sqrt[3]{7^3} = 2 \times 7
\]
**Hint:** Remember that \( \sqrt[3]{a^3} = a \).
### Step 7: Calculate the final answer
Now we can calculate:
\[
2 \times 7 = 14
\]
So, the cube root of 2744 is:
\[
\sqrt[3]{2744} = 14
\]
### Final Answer:
The cube root of 2744 is **14**.
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