The difference between is 2-digit number and the number obtained by intercanging its digits is 63. What is the difference between the digits of the number?

Answer

To solve the problem, we need to find the difference between the digits of a two-digit number, given that the difference between the number and the number obtained by interchanging its digits is 63.

### Step-by-Step Solution:

1. **Define the Digits**:
Let the two-digit number be represented as \( 10x + y \), where \( x \) is the tens digit and \( y \) is the units digit.

2. **Interchange the Digits**:
When the digits are interchanged, the new number becomes \( 10y + x \).

3. **Set Up the Equation**:
According to the problem, the difference between the original number and the number with interchanged digits is 63. Therefore, we can write the equation:
\[ (10x + y) - (10y + x) = 63 \]

4. **Simplify the Equation**:
Simplifying the left side of the equation:
\[ 10x + y - 10y - x = 63 \]
This simplifies to:
\[ 9x - 9y = 63 \]

5. **Factor Out the Common Term**:
We can factor out 9 from the left side:
\[ 9(x - y) = 63 \]

6. **Solve for the Difference**:
Dividing both sides by 9 gives:
\[ x - y = 7 \]

7. **Conclusion**:
The difference between the digits \( x \) and \( y \) is 7.

### Final Answer:
The difference between the digits of the number is **7**.