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Replace A,B and C by suitable numerals. ...

Replace A,B and C by suitable numerals. `({:(," "4CB6),(,+369A):})/(" "8173)`

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To solve the problem of replacing A, B, and C with suitable numerals in the equation \((4CB6) + (369A) = 8173\), we will follow these steps: ### Step 1: Set Up the Equation We start with the equation: \[ (4CB6) + (369A) = 8173 \] ### Step 2: Identify the Last Digit We look at the last digits of both numbers: - The last digit of \(4CB6\) is \(6\). - The last digit of \(369A\) is \(A\). Adding these gives: \[ 6 + A \equiv 3 \mod 10 \] This means that \(6 + A\) must end in 3. The possible values for \(A\) can be calculated as follows: - If \(A = 7\), then \(6 + 7 = 13\) (last digit is 3). Thus, we have: \[ A = 7 \] ### Step 3: Substitute A and Analyze the Next Column Now we substitute \(A\) into the equation: \[ (4CB6) + (3697) = 8173 \] ### Step 4: Identify the Second Last Digit Next, we look at the second last digits: - The second last digit of \(4CB6\) is \(B\). - The second last digit of \(3697\) is \(9\). Adding these gives: \[ B + 9 + 1 \equiv 7 \mod 10 \] (The \(1\) is the carry from the previous addition of \(6 + 7\)). This simplifies to: \[ B + 10 \equiv 7 \mod 10 \] Thus, \(B\) must be: \[ B = 7 - 10 = -3 \quad \text{(not possible)} \] So we try \(B + 9 + 0 \equiv 7 \mod 10\): \[ B + 9 \equiv 7 \mod 10 \] This means: \[ B \equiv 7 - 9 \equiv -2 \equiv 8 \mod 10 \] Thus, we have: \[ B = 8 \] ### Step 5: Substitute B and Analyze the Third Column Now we substitute \(B\) into the equation: \[ (48C6) + (3697) = 8173 \] ### Step 6: Identify the Third Last Digit Next, we look at the third last digits: - The third last digit of \(48C6\) is \(C\). - The third last digit of \(3697\) is \(6\). Adding these gives: \[ C + 6 + 1 \equiv 1 \mod 10 \] (The \(1\) is the carry from the previous addition of \(B + 9\)). This simplifies to: \[ C + 7 \equiv 1 \mod 10 \] Thus: \[ C \equiv 1 - 7 \equiv -6 \equiv 4 \mod 10 \] Thus, we have: \[ C = 4 \] ### Final Values Now we have found: - \(A = 7\) - \(B = 8\) - \(C = 4\) ### Conclusion The values of A, B, and C are: \[ A = 7, \quad B = 8, \quad C = 4 \]
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