Replace A,B,C by suitable numberals:
`({:(," "57A),(,""-CB8):})/(" "293)`

Answer

To solve the problem, we need to replace A, B, and C with suitable numerals in the expression `({:(," "57A),(,""-CB8):})/(" "293)`. Let's break down the steps to find the values of A, B, and C.

### Step-by-Step Solution:

1. **Understand the Expression**:
The expression can be interpreted as:
\[ \frac{(57A - CB8)}{293} \]
We need to find values for A, B, and C such that this expression holds true.

2. **Analyze the Units Place**:
Start with the units place of the numbers involved. The units place of `57A` is A, and the units place of `CB8` is 8. We need to find A such that:
\[ A - 8 \equiv 3 \mod 10 \]
This means that A must be 1 because:
\[ 1 - 8 = -7 \equiv 3 \mod 10 \]
(We can think of this as borrowing 1 from the next column.)

**Hint**: Check the units place first to determine A.

3. **Determine the Tens Place**:
Now, consider the tens place. The tens place of `57A` is 7, and we need to subtract the tens place of `CB8` which is B. Since we borrowed 1 from the hundreds place, we have:
\[ 6 - B \equiv 9 \mod 10 \]
This means:
\[ 6 - B = 9 \implies B = 6 - 9 = -3 \quad \text{(not possible)} \]
Instead, we should consider the carry from the hundreds place:
\[ 16 - B = 9 \implies B = 16 - 9 = 7 \]

**Hint**: Use the carry from the previous column to adjust the subtraction.

4. **Determine the Hundreds Place**:
Now, for the hundreds place, we have:
\[ 5 - C \equiv 2 \mod 10 \]
This means:
\[ 5 - C = 2 \implies C = 5 - 2 = 3 \]

**Hint**: Solve for C using the hundreds place after accounting for any carry.

5. **Final Values**:
After solving the above equations, we find:
- A = 1
- B = 7
- C = 3

### Conclusion:
The suitable numerals to replace A, B, and C are:
- A = 1
- B = 7
- C = 3