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The value of a machine depreciates at th...

The value of a machine depreciates at the rate of 10% per annum. It was purchased 3 years ago. If its present value is Rs 291600. for how much it purchased?

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To find the purchase price of the machine, we can use the formula for depreciation. The present value (PV) of an asset after depreciation can be calculated using the formula: \[ PV = P \times \left(1 - \frac{R}{100}\right)^T \] Where: - \( PV \) = Present Value (Rs. 291600) - \( P \) = Principal or Purchase Price (what we need to find) - \( R \) = Rate of depreciation (10%) - \( T \) = Time in years (3 years) ### Step 1: Write down the formula for present value after depreciation We start with the formula: \[ PV = P \times \left(1 - \frac{R}{100}\right)^T \] ### Step 2: Substitute the known values into the formula Substituting the known values into the formula: \[ 291600 = P \times \left(1 - \frac{10}{100}\right)^3 \] ### Step 3: Simplify the expression inside the parentheses Calculate \( 1 - \frac{10}{100} \): \[ 1 - \frac{10}{100} = 1 - 0.1 = 0.9 \] So now our equation becomes: \[ 291600 = P \times (0.9)^3 \] ### Step 4: Calculate \( (0.9)^3 \) Now calculate \( (0.9)^3 \): \[ (0.9)^3 = 0.9 \times 0.9 \times 0.9 = 0.729 \] Now the equation is: \[ 291600 = P \times 0.729 \] ### Step 5: Solve for \( P \) To find \( P \), divide both sides by \( 0.729 \): \[ P = \frac{291600}{0.729} \] ### Step 6: Perform the division Now calculate the division: \[ P = 400000 \] ### Conclusion The purchase price of the machine was Rs. 400000. ---
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RS AGGARWAL-COMPOUND INTEREST -EXERCISE 11B
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  8. At what rate per cent per annum will Rs 4000 amount to Rs 4410 in 2 ye...

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  9. At what rate per cent per annum will Rs 640 amount to 774.40 in 2 year...

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  10. In how many years will Rs 1800 amount to Rs 2178 at 10% per annum when...

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  11. In how many years will Rs 6250 amount to Rs 7290 at 8% per annum, comp...

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  13. Three years ago, the population of a town was 50000. If the annual inc...

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  14. The population of a city was 120000 in the year 2013 . During next yea...

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  16. The bacteria in a culture grows by 10% in the first hour, decreases by...

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