Home
Class 8
MATHS
In the adjoining figure , ABCD is a par...

In the adjoining figure , ABCD is a parallelogram in which `angleCAD=40^@, angleBAC=35^@` and `angleCOD=65^@` Calculate : (i)`angleABD` (ii)`angleBDC` (iii)`angleACB` (iv) `angleCBD`

Promotional Banner

Topper's Solved these Questions

  • PARALLELOGRAMS

    RS AGGARWAL|Exercise Exercise 16A|28 Videos
  • PARALLELOGRAMS

    RS AGGARWAL|Exercise Exercise 16B|10 Videos
  • OPERATIONS ON ALGEBRAIC EXPRESSIONS

    RS AGGARWAL|Exercise Exercise 6E (Tick the correct answer in each of the following:)|19 Videos
  • PERCENTAGE

    RS AGGARWAL|Exercise TEST PAPER -9 ( TRUE AND FALSE )|4 Videos

Similar Questions

Explore conceptually related problems

In the adjoining figure, ABCD is a parallelogram in which angleBAD=75^@ and angleDBC=60^@ .Calculate (i) angleCDB and (ii) angleADB

In Figure, A B C D is a parallelogram in which /_D A O=40^0, /_B A O=35^0 a n d /_C O D=65^0dot Find: /_A B O (ii) /_O D C (iii) /_A C B (iv) /_C B D

In the adjoining figure, ABCD is a square and PAB is an equilateral triangle. Find : (i) angleAPD (ii) anglePDC (iii) angleDPC (iv) Prove that DP = CP

In the given figure, ABCD is a parallelogram in which AN and CP are perpendiculars on diagonal BD. Prove that : (i) DeltaADN =DeltaCBP (ii) AN=CP

In the given figure, ABCD is a quadrilateral in which AD = BC and angleDAB=angleCBA. Prove that (i) DeltaABD~=DeltaBAC, (ii) BD = AC, (iii) angleABD=angleBAC.

In the adjoining figure ABCD is a parallelogram, ABM is a line segment and E is the mid-point of BC. Prove that : (i) DeltaDCE cong DeltaMBe (ii) AB = BM (iii) AM=2DC

In DeltaABC sides AB and C are produced to D and E respectively. Bisectors of exterior angles so formed interest each other at point I. If angleBAC=80^(@) and angleACB=50^(@) Find, (i) angleECB (ii) angleDBC (iii) angleICB (iv) angleIBC (v) angleBIC

In the adjoining figure, (i) Which side is smallest ? (ii) In DeltaABC , what is the nature of angleBAC ?

The give figure shows a square ABCD and an equilayeral teiangle APB. Calculate : {:((1)angleAOB,(ii)angleBPC),((iii)anglePCD,(iv)"reflex"angleAPC):}

In the adjoining figure, angleBAC=angleBDC and angleABC=angleBCD . Prove that : (i) DeltaABC cong DeltaDCB (ii) DeltaABE cong DeltaDCF .