Evaluate: `int1/((x-alpha)(beta-x))dx ,(beta>alpha)`

Evaluate: int(1)/((x-alpha)(beta-x))dx,(beta>alpha)

Evaluate : int(dx)/((x-alpha)(beta-x))beta gt alpha

int(dx)/(sqrt((x-alpha)(beta-x)))

Evaluate: int_(alpha)^(beta)(dx)/(sqrt((x-alpha)(beta-x)))dx

Evaluate the following intergrals : int sqrt((x-alpha)(beta-x))dx(alpha lt x lt beta)

Integrate : int (dx)/(sqrt((x-alpha)(beta-x)))[ alpha lt x lt beta]

The value of the integral int_alpha^beta (1)/(sqrt((x-alpha)(beta-x)))dx " for "beta gt alpha , is

int (dx)/(sqrt((x-alpha)(x-beta)))

If alpha and beta are the zeroes of the polynomial f(x) = 5x^(2) - 7x + 1 , then find the value of ((alpha)/(beta) + (beta)/(alpha)) .

int _(alpha)^(beta) 2x dx is equal to