f(x)={[(k cos x)/(pi-2x),x<(pi)/(2)],[3,x=(pi)/(2)],[(3tan2x)/(2x-pi),,x>(pi)/(2)]

For f(x)=(k cos x)/(pi-2x), if x!=(pi)/(2),3, if x=(pi)/(2) then find the value of k so that f is continous at x=(pi)/(2)

Let f(x)=(k cos x)/(pi-2x) if x!=(pi)/(2) and f(x=(pi)/(2)) if x=(pi)/(2) then find the value of k if lim_(x rarr(pi)/(2))f(x)=f((pi)/(2))

Let f(x)={:{((kcosx)/(pi-2x)',xne(pi)/(2)),(3",",x=(pi)/(2).):} If lim_(xto(pi)/(2))f(x)=f((pi)/(2)), find the value of k.

Let f(x)={:{((kcosx)/(pi-2x)',xne(pi)/(2)),(3",",x=(pi)/(2).):} If lim_(xrarr(pi)/(2))f(x)=f((pi)/(2)), find the value of k.

Find k if the function is continuous at x=(pi)/(2) if (a) f(x)={{:((k cos x )/(pi-2x),x ne (pi)/(2)),(3,if x=(pi)/(2)):} at x=(pi)/(2) (b) f(x)={{:(kx+1, if x le 2),(cos x,if x gt 2):} at x=2 (c ) if f(x)={{:(k^(2)x-k,if x le 1),(2 , if x lt 1):} is continous on R then find the value (s) of k

Find the value of k if f(x) is continuous at x=pi/2, where f(x)={(k cos x)/(pi-2x),quad x!=pi/23,quad x=pi/2

Determine the value of k, if f(x) = {((kcosx)/(pi-2x),if x!=(pi)/2),(3,if x = (pi)/2):}

Find the value of k if f(x) is continuous at x=pi//2 , where f(x)={(kcosx)/(pi-2x),x!=pi/2 \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ 3, \ \ \ \ \ \ \ \ \ x=pi/2

Find the value of k so that the function f is continuous at x=pi//2,f(x)={:{((kcosx)/(pi-2x)", if "x!=(pi)/(2)),(5", if "x=(pi)/(2)):}

If f(x) = {{:((k cos x)/(pi - 2x), x ne pi//2),(1, x = pi//2):} , is a continous function at x = pi//2 , then the value of k is-