Calculate the angular momentum of the earth rotating about its own axis. Mass of the earth `= 5.98 xx 10^(27)` kg, mean radius of the earth `=6.37 xx 10^(6)m,M.I` of the earth `= (2)/(5)MR^(2)`.

The value of angular momentum of the earth rotating about its own axis is

Calculate the angular momentum of earth rotating about its own axis. Take Radius of earth =6.4xx10^(6)m Mass of earth =5.97xx10^(24)kg

Calculate angular momentum of earth rotating about its axis. Take I = (2)/(5)MR^(2) , where M = 6 xx 10^(24) kg and R = 6400 Km .

Calculate the angular momentum and rotational kinetic energy of the earth about its own axis. Given mass of the earth is 6 xx 10^(24) kg and its radius = 6.4 xx 10^3 km. [Moment of inertia of the earth about its axis of rotation is 2/5 mr^(2) ]

Calculate the mass and density of the earth. Given that Gravitational constant G = 6.67 xx 10^(-11) Nm^(2)// kg^(2) , the radius of the earth = 6.37 xx 10^(6) m and g = 9.8 m//s^(2) .

What is the value of g at a height 8848 m above sea level. Given g on the surface of the earth is 9.8 ms^(-2) . Mean radius of the earth = 6.37 xx 10^(6) m .

A rocket is fired vertically with a speed of 5 km s^(-1) from the earth’s surface. How far from the earth does the rocket go before returning to the earth ? Mass of the earth = 6.0 x× 10^(24) kg, mean radius of the earth = 6.4 xx 10^(6) m , G = 6.67 xx 10^(-11) " N "m^(2) kg^(-2) .