[" A projectile is given an initial velocity "i+2j" .The cartesian equation of "],[" its path is "^((g=10ms^(-2)))]

A projectile is given an initial velocity hati+2 hatj .The cartesin equation of its path is (g=10ms^(-2))

A projectile is given an initial velocity hati+2 hatj .The cartesin equation of its path is (g=10ms^(-2))

A projectile is given an initial velocity of hat i+2hatj . The Cartesian equation of its path is (g= 10 m/s^2

" A projectile is given an initial velocity "hat i+2hat j" .The cartesian equation of its path is "[" take "g=10m/s^(2)]

A projectile is given an initial velocity of (hat(i)+2hat(j)) The Cartesian equation of its path is (g = 10 ms^(-1)) ( Here , hati is the unit vector along horizontal and hatj is unit vector vertically upwards)

A projectile is given an initial velocity of (hat(i)+2hat(j)) The Cartesian equation of its path is (g = 10 ms^(-1)) ( Here , hati is the unit vector along horizontal and hatj is unit vector vertically upwards)

A projectile is given an initial velocity of hat t + 2.hatj . Find the cartisian equation of its path. (g = 10 ms^-1) .

A projectile is given an initial velocity of ( hat (i) + 2 hat (j)) ms^(-1) . The equation of its path is (g= 10 ms^(-2))

A particle is projected with initial velocity of hati+2hatj . The eqaution of trajectory is (take g=10ms^(-2))

A projectile is projected with the initial velocity (6i + 8j) m//s . The horizontal range is (g = 10 m//s^(2))