(x-4)/(1)=(y-2)/(1)=(z-k)/(2)" lies in the plane "2x-4y+z=7

The value of K such that the line (x-4)/(1)=(y-2)/(1)=(z-k)/(2) lies in the plane 2x-4y+pz=7 is

Write the value of k such that the line (x-4)/1=(y-2)/1=(z-k)/2 lies on the plane 2x-4y+z=7

The value of k such that the line (x-4)/1=(y-2)/1=(z-k)/2 lies on the plane 2x - 4y + z = 7 is

If the line (x-4)/(1)=(y-2)/(1)=(z-k)/(2) lies exactly on the plane 2x-4y+z=7 , the value of k is

If the line (x-4)/(1)=(y-2)/(1)=(z-k)/(2) lies exactly on the plane 2x-4y+z=7 , the value of k is

If the line (x-4)/(1)=(y-2)/(1)=(z-k)/(2) lies exactly on the plane 2x-4y+z=7 , the value of k is

If the line (x-4)/(1)=(y-2)/(1)=(z-k)/(2) lies exactly on the plane 2x-4y+z=7 , the value of k is

The line (x-4)/1=(y-2)/1=(z-k)/2 lies exactly on the plane 2x-4y+z=7 then the value of k is (A) 7 (B) -7 (C) 1 (D) none of these

The line (x-4)/1=(y-2)/1=(z-k)/2 lies exactly on the plane 2x-4y+z=7 , then the value of k is :