A current of `1 A` is drawn by a filament of an electric bulb. Number of electrons passing through a cross-section of the filament in `16` seconds would be roughly :

Options

A. `10^(20)`
B. `10^(16)`
C. `10^(18)`
D. `10^(23)`

Answer

A

Explanation

Given, current, I = 1 A
Time, t = 16 s
Number of electrons n = ?
We know that,
Current, `I = (Q)/(t) = ("ne")/(t)` `" "[because e = "Charge of an electron" = 1.6 xx 10^(-19)C and Q = "ne"]`
`rArr` `" "n = (It)/(e) = (1 xx 16)/(1.6 xx 10^(-19)) = 10^(20)`