What is the minimum resistance which can be made using five resistors each of `(1//5) Omega` ?

Options

A. `1//5 Omega`
B. `1//25 Omega`
C. `1//10 Omega`
D. `25 Omega`

Answer

B

Explanation

The minimum resistance is obtained when resistors are connected in parallel combination. Thus, equivalent resistance,
`R_(P) = (R)/(n) = (1//5)/(5) = (1)/(25) Omega, R_(p)` = equivalent resistance for parallel combination.