" Let "A=[[1,-1,1],[2,1,-3],[1,1,1]]" and "b=(1)/(10)[[4,2,2],[-5,0,k],[1,-2,3]]" If "B

Let A = [(1,-1,1),(2,1,-3),(1,1,1)] and (10)B = [(4,2,2),(-5,0,alpha),(1,-2,3)] If B is the inverse of A , then alpha is :

Let A =[(1,-1,1),(2,1,-3),(1,1,1)] and 10B=[(4,2,2),(-5,0,alpha),(1,-2,3)] . If B is the inverse of A, then alpha is :

Let A =[(1,-1,1),(2,1,-3),(1,1,1)] and 10B=[(4,2,2),(-5,0,alpha),(1,-2,3)] . If B is the inverse of A, then alpha is :

Let A =[(1,-1,1),(2,1,-3),(1,1,1)] and 10B=[(4,2,2),(-5,0,alpha),(1,-2,3)]. If B is the inverse of A, then alpha is :

Let A =[(1,-1,1),(2,1,-3),(1,1,1)] and 10B=[(4,2,2),(-5,0,alpha),(1,-2,3)] . If B is the inverse of A, then find the value of alpha

Let A =[(1,-1,1),(2,1,-3),(1,1,1)] and 10B=[(4,2,2),(-5,0,alpha),(1,-2,3)] . If B is the inverse of A, then alpha is :

Let A = [(1,-1,1),(2,1,-3),(1,1,1)] and 10B = [(4,2,2),(-5,0, alpha),(1,-2,3)] If B is the inverse of A, then find the value alpha .

Let A=[(1,-1,1),(2,1,-3),(1,1,1)] and B=[(4,2,2),(-5,0,alpha),(1,-2,3)] If B is the inverse of matrix A , then alpha= (A) 2 (B) -2 (C) 5 (D) -5