A point p is such that the sum of squares of its distance from the axes of coordinates is equal to the square of its distance from the line `x-y =1`. Find the locus of P

A point P is such that the sum of the squares of its distances from the two axes of co-ordinates is equal to the square of its distance from the line x-y=1 . Find the equation of the locus of P.

Locus of point for which the sum of squares of distance from the coordinate axes is 8 units is

A point moves such that the sum of the squares of its distances from the sides of a square of side unity is equal to 9, the locus of such point is

A point moves such that the sum of the squares of its distances from the sides of a square of side unity is equal to 9, the locus of such point

A point moves such that the sum of the squares of its distances from the sides of a square of side unity is equal to 9, the locus of such point is

A point moves such that the sum of the squares of its distances from the two sides of length a of a rectangle is twice the sum of the squares of its distances from the other two sides of length b.The locus of the point can be:

If the sum of the squares of the distance of a point from the three coordinate axes is 36, then find its distance from the origin.

If the sum of the squares of the distance of a point from the three coordinate axes is 36, then find its distance from the origin.

If the sum of the squares of the distance of a point from the three coordinate axes is 36, then find its distance from the origin.