If `f: [-6, 6] -> RR` is defined by `f(x)=x^2-3` for `x in RR` then `(fofof)(-1)+(fofof)(0)+(fofof)(1)=`

If f:[-6, 6]rarr RR defined by f(x)=x^(2)-3" for " x in R then (fofof)(-1)+(fofof)(0)+(fofof)(1)=

Let f : [-6,6] -> R be defined by f(x) = x^2-3. Consider the following 1. (fofof)(-1) = (fofof)(1) 2. (fofof)(-1) - 4(fofof)(1) = (fof)(0) : Which of the above is/are correct?

If f(x)=-|x| , then (fofof)=

If f(x)= x−1 x+1 ​ (x  =±1) then find i) (fofof)(x) ii) (fofofof)(x)

If f:R to R be defined by f(x) = (x)/(sqrt(1 +x^(2) )), then (fofof)(x)= …………. .

If f:R to R be defined by f(x) = (x)/(sqrt(1 +x^(2) )), then (fofof)(x)= …………. .