[(6)/(x+y)=(7)/(2-y)+3],[(1)/(2cos y)=(1)/(3(x-y))]

(6)/(x+y)=(7)/(x-y)+3(1)/(2(x+y))=(1)/(3(x-y))

6/(x+y)=7/(x-y)+3 , 1/(2(x+y))=1/(3(x-y))

Solve by cross-multiplication method. (i) 8x-3y=12,5x=2y +7 (ii) 6x+ 7y -11 =0, 5x+ 2y =13 (iii) (2)/(x)+(3)/(y) =5, (3)/(x) -(1)/(y) +9=0

(x)/(2) - ( y )/(9) = 6, ( x) /( 7) + ( y ) /(3) = 5 .

Solve for x and y : (y+7)/(5)=(2y-x)/(4)+3x-5 (7-5x)/(2)+(3-4y)/(6)=5y-18

Simplify : (i) (5x - 9y) - (-7x + y) (ii) (x^(2) -x) -(1)/(2)(x - 3 + 3x^(2)) (iii) [7 - 2x + 5y - (x -y)]-(5x + 3y -7) (iv) ((1)/(3)y^(2) - (4)/(7)y + 5) - ((2)/(7)y - (2)/(3)y^(2) + 2) - ((1)/(7)y - 3 + 2y^(2))

Factorize each of the following algebraic expressions: 6x(2x-y)7y(2x-y)2r(y-x)+s(x-y)7a(2x-3)+3b(2x-3)9a(6a-5b)-12a^(2)(6a-5b)

If (x)/(y)=(6)/(5), then the value of ((6)/(7)-(5x-y)/(5x+y)) is equal to (a) (1)/(7)( b) (2)/(7)(c)(3)/(7) (d) (4)/(7)

Simplify (i) (6 x-2 y)+(3 x+4 y) ii) (x-2 y)-(2 x-y) iii) (5+3 x)+(3-2 x) iv) (4 x-2 y)-(6 x-7 y)