A solution contains 50 mL of alcohol mixed with 150 mL of water. Calculate the concentration of this solution .

Options

A. 30%
B. 25%
C. 75%
D. 50%

Answer

B

Explanation

This solution contains of this liquid solute (alcohol) mixed with a liquid solvent (water), so we have to calculate the concentration of this solution in terms of volume percentage of solute (alcohol). (Now, we know that :
Concentration of solution `=("Volume of solute")/("Volume of solution ")xx100`
Here, Volume of solute (alcohol) = 50mL and Volume of solvent (water) = 150mL
So, Volume of solution = Volume of solute + Volume of Solvent
`=50+150`
`=200mL `
Now, putting these values of volume of solute and volume of solution in the the above formula we get :
Concentration of sodium `=(50)/(200)xx100 = (50)/(2) = 25 %` (by volume )
Thus , the concentration of this alcohol solution is 25 per cent or that it is a 25% alcohol solution (by volume ).