`12` grams of potassium sulphate dissolves in `75` grams of water at `60^(@) C`, what is its solubility in water at that temperature ?

Options

A. `16` g
B. `20` g
C. `26` g
D. `6` g

Explanation

To find the solubility of potassium sulfate in water at 60°C, we will follow these steps:

### Step-by-Step Solution:

1. **Understand the Problem**: We know that 12 grams of potassium sulfate (K₂SO₄) dissolves in 75 grams of water at 60°C. We need to find out how much potassium sulfate would dissolve in 100 grams of water at the same temperature.

2. **Set Up the Proportion**: We can set up a proportion based on the amount of potassium sulfate that dissolves in the given amount of water. We know:
- 12 grams of K₂SO₄ dissolves in 75 grams of water.

3. **Calculate the Amount of K₂SO₄ per Gram of Water**: To find out how much K₂SO₄ dissolves in 1 gram of water, we divide the amount of K₂SO₄ by the amount of water:
\[ \text{Amount of K₂SO₄ per gram of water} = \frac{12 \text{ grams}}{75 \text{ grams}} = 0.16 \text{ grams of K₂SO₄ per gram of water} \]

4. **Calculate for 100 grams of Water**: Now, we can find out how much K₂SO₄ would dissolve in 100 grams of water by multiplying the amount of K₂SO₄ per gram of water by 100:
\[ \text{Amount of K₂SO₄ in 100 grams of water} = 0.16 \text{ grams/g} \times 100 \text{ grams} = 16 \text{ grams} \]

5. **Conclusion**: Therefore, the solubility of potassium sulfate in water at 60°C is 16 grams.

### Final Answer:
The solubility of potassium sulfate in water at 60°C is **16 grams**.

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