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100 mL of water at room temperature o...

100 mL of water at room temperature of `25^(@)C` is taken in a beaker and a little of solid S s is dissolved in it by stirring of obtain a solution X. More and more of solid S is added to the solution with constant stirring while keeping the temperature of solution constant at `30^(@)` C After some time it is observed that no more solid dissolves in water and it the same time some solid is also left undissolved at the bottom of the beaker . the contents of beaker are filtered through a filter paper to obtain solution Y in the from of a filtrate .
(a) what name is given to solutions like X ?
( b) what name is given to solutions like Y ?
(c ) what will you observe it the solution y `30^(@)C` is cooled down to `10^(@)C` by keeping the beaker in crushed ice ? why ?
(d ) what term is used to denote the amount of solid dissolved in 100 grams of water in a solution like Y ?

Text Solution

Verified by Experts

The correct Answer is:
(a) Unsatureated solution (b) saturated solution ( C) some of the dissolved solid will separate from the solution and settle down at the bottom of the beaker ; because the solubility of solid decrease on cooling (d) Solubility
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