How many grams of oxygen gas contain the same number of molecules as `16` grams of sulphur dioxide gas ? `(O = 16 u , S = 32 u)`

Explanation

This problem will be solved by using the fact that equal moles of all the gases contains equal number of molecules. Let us first convert 16 grams of sulphur dioxide into moles.
1 moles of sulphur dioxide, ` SO_(2) = "Mass of S" + "Mass of 2 'O'"`
` = 32 + 2 xx 16`
`= 64` grams
Now, `64 g` of sulphur dioxide, `= 1` mole
So, `16g` of sulphur dioxide ` = 1/64 xx 16` mole
` = 1/4` mole
Now, `1/4` mole of sulphur dioxide will have the same number of molecular as `1/4` mole of oxygen. So, we should now convert `1/4` mole of oxygen into mass in grams.
`1` mole of oxygen, `O_(2)` = Mass of `2 'O'` atoms
`= 2 xx 16`
`= 32` grams
Now, `1` mole of oxygen ` = 32` grams
So, `1/4` mole of oxygen `= 32 xx 1/4` grams
`= 8` grams
Thus, 8 grams of oxygen will contain the same number of molecules as `16` grams of sulphur dioxide.