A car of mass 2400 kg moving with a velocity of 20 m s^(-1) is stopped in 10 seconds on applying brakes Calculate the retardation and the retarding force.
A car is moving at a speed of 72 km//h . The diamter of its whells is 0.5 m . If the wheels are stopped in 20 rotations by applying brakes, calcualte the angular retardation produced by the brakes.
The speed of a moving car is 60kmh^(-1) . The wheels having diameter of 0.60 m are stopped in 10 rotations by applying brakes. What will be the angular retardation produced by brakes?
A car is moving at a speed of 72 kmh^(-1) . The diameter of its wheel is 0.50m. If the wheels are stopped in 20 rotations by applying brakes, calculate the angular retardation produced by the brakes.
Find the initial velocity of a car which is stopped in 10 seconds by applying brakes. The retardation due to brakes is 2.5 m/ s^(2) .
A bus was moving with a speed of 54 km//h . On applying brakes , it stopped in 8 seconds . Calculate the acceleration and the distance travelled before stopping.
(a) Derive the formula : v= u+at , where the symbols have usual meanings. (b) A bus was moving with a speed of 54 km/h. On applying brakes it stopped in 8 seconds. Calculate the acceleration.
A train running at 108 km//h is brought to a halt in 2 minutes. Calculate the retardation produced by the application of brakes. Also, calculate the distance the train travels before stopping.
A scooter moving at a speed of 10 m/s is stopped by applying brakes which produce a uniform acceleration of, -0.5 m/ s^(2) . How much distance will be covered by the scooter before it stops ?
LAKHMIR SINGH & MANJIT KAUR-MODEL TEST PAPER 2-SECTION B
