Two metals X and Y form the salts `XSO_(4)` and `Y_(2)SO_(4)` respectively.The solution of salt `XSO_(4)` is blue in colour whereas that of `Y_(2)SO_(4)` is formed alongiwth a salt Which turns the solution green. And when barium chloride solution is added to `Y_(2)SO_(4)` solution, then the same white precipitate Z is formed alongwith colourless common salt solution.
(a) What could the metal X and Y be ?
(b) Write the name and formula of salt `XSO_(4)`
(c) Write the name and formula of salt `X_(2)SO_(4)`
(d)What is the name and formula of white precipate Z ?
(e) Write the name and formula of the salt which turns the solution green in the first case.

Answer

(a) Metal X: Copper; Metal Y : Sodium (b) Copper sulphate, `CuSO_(4)` (c) Sodium sulphate, `Na_(2)SO_(4)` (d)Barium sulphate, `BaSO_(4)` (e) Copper chloride , `CuCl_(2)`