A body of mass 5 kg is moving with a velocity of 10 m/s. A force is applied to it so that in 25 seconds, it attains a velocity of 35 m/s. Calculate the value of the force applied.

Answer

To solve the problem, we need to calculate the force applied to a body of mass 5 kg that changes its velocity from 10 m/s to 35 m/s over a period of 25 seconds. We will follow these steps:

### Step 1: Identify the known values
- Mass (m) = 5 kg
- Initial velocity (u) = 10 m/s
- Final velocity (v) = 35 m/s
- Time (t) = 25 s

### Step 2: Calculate the acceleration (a)
We can use the formula for acceleration:
\[ a = \frac{v - u}{t} \]
Substituting the known values:
\[ a = \frac{35 \, \text{m/s} - 10 \, \text{m/s}}{25 \, \text{s}} = \frac{25 \, \text{m/s}}{25 \, \text{s}} = 1 \, \text{m/s}^2 \]

### Step 3: Calculate the force (F)
Now that we have the acceleration, we can calculate the force using Newton's second law of motion:
\[ F = m \cdot a \]
Substituting the known values:
\[ F = 5 \, \text{kg} \cdot 1 \, \text{m/s}^2 = 5 \, \text{N} \]

### Final Answer
The value of the force applied is **5 Newtons (N)**.

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