Solve the differential equation `(df(x))/dx+ f(x).g'(x) = g(x).g'(x)`. It is known that the curves `y = f(x)` and `y = g(x)` pass through `(1, 1)`.

If (d)/(dx)f(x)=g(x), then int f(x)g(x)dx is equal to:

If d/(dx) f(x) = g (x) , then int_a^b f(x) g(x) dx is:

Differential equation (dy)/(dx)=f(x)g(x) can be solved by separating variable (dy)/g(y)=f(x)dx. The equation of the curve to the point (1,0) which satsifies the differential equation (1+y^(2))dx-xydy=0 is

Differential equation (dy)/(dx)=f(x)g(x) can be solved by separating variable (dy)/g(y)=f(x)dx. The equation of the curve to the point (1,0) which satsifies the differential equation (1+y^(2))dx=xydy=0 is

If (d)/(dx) f(x) = g(x) then int_(a)^(b) f(x) g(x) dx=

Differential equation (dy)/(dx)=f(x)g(y) can be solved by separating variable (dy)/g(y)=f(x)dx. The equation of the curve to the point (1,0) which satsifies the differential equation (1+y^(2))dx=xydy=0 is

Differential equation (dy)/(dx)=f(x)g(y) can be solved by separating variable (dy)/g(y)=f(x)dx. The equation of the curve to the point (1,0) which satsifies the differential equation (1+y^(2))dx=xydy=0 is

We say an equation f(x)=g(x) is consistent, if the curves y=f(x) and y=g(x) touch or intersect at atleast one point. If the curves y=f(x) and y=g(x) do not intersect or touch, then the equation f(x)=g(x) is said to be inconsistent i.e. has no solution. The equation cosx+cos^(-1)x=sinx+sin^(-1)x is