Fig, here shows P and Q as two equally intense coherent sources emitting radiations of wavelength 20m. The separation PQ si 5m, and phase of P is ahead of the phase Q by `90^(@)`. A, B and C are three distant points of observation equidistant from the mid - point of PQ. The intensity of radiations of A, B, C will be in the ratio

Fig, here shows P and Q as two equally intense coherent sources emitting radiations of wavelength 20m. The separation PQ si 5m, and phase of P is ahead of the phase Q by 90^(@) . A, B and C are three distant points ofobservation equidistant from the mid - point of PQ. The intensity of radiations of A, B, C will beasr the ratio

If A=(1,2,3) and B(3,5,7) and P,Q are the points on AB such that AP=PQ=QB , then the mid point of PQ is

S_(1) and S_(2) are two equally intense coherent point second sources vibrating in phase. The resultant intensity at P_(1) is 80 SI units then resultant intensity at P_(2) in SI units will be

Two coherent point sources S_1 and S_2 vibrating in phase emit light of wavelength lamda . The separation between them is 2lamda . The light is collected on a screen placed at a distance Dgt gt lamda from the slit S_1 as shown. The minimum distance, so that intensity at P is equal to the intensity at O

A point source of constant power P is emitting photon of wavelength lambda . What is the intensity of photons at r distance from the source ?(speed of light = c)

Two waves are propagating to the point P along a straight line produced by two sources A and B of simple harmonic and of equal frequency. The amplitude of every wave at P is a and the phase of A is ahead by pi//3 than that of B and the distance AP is greater than BP by 50 cm . Then the resultant amplitude at the point P will be if the wavelength 1 meter

In the given figure, AB is a line segment. P and Q are points on opposite sides of AB such that each of them is equidistant from the points A and B. Show that the line PQ is the perpendicular bisector of AB.