If a closed pipe has length land velocity of sound is V then formulae for `2^(nd)` overtone in it is

When a closed organ pipe of length l if the velocity of sound is v then the fundamental frequency will be

f length of a closed organ pipe is 1 m and velocity of sound is 330 m//s , then the frequency is-

An open and a closed pipe have same length ratio of frequencies of their nth overtone is

(iv) A closed organ pipe of length 83.2 cm and 6 cm diameter is vibrated. The velocity of sound is 340 m/s. find the number of overtones in this tube having frequency below 1000 Hz ?

Length of an organ pipe open at both ends in 33.3 cm. If velocity of sound is 333 m/s.,then the frequency of fifth overtone is

The first overtone of an open organ pipe(of length L_(0) ) beats with the first overtone of a closed organ pipe(of length L_(c) ) with a beat frequency of 10Hz.The fundamental frequency of the closed pipe is 110Hz .If the speed of sound is 330ms then fundamental frequency of open pipe is ?

The frequency of the third overtone of a closed pipe of length L_(c) is the same as the frequency of the sixth overtone of an open pipe of the length L_(o). Then

A closed organ pipe has length 'l'. The air in it is vibrating in 3^(rd) overtone with maximum displacement amlitude 'a'. The displacement amplitude at distance l"/"7 from closed end of the pipe is :

The fundamental frequency of a closed pipe is 220 H_(Z) . (a) Find the length of this pipe. (b) The second overtone of this pipe has the same frequency as the third harmonic of an open pipe. Find the length of this open pipe. Take speed of sound in air 345 m//s .

if the first overtone of a closed pipe of length 50 cm has the same frequency as the first overtone of an open pipe, then the length of the open pipe is