An electron in Bohr's hydrogen atom has angular momentum `(2h)/(pi)` The energy of the electron is

An electron in Bohr's hydrogen atom has an energy of -3.4 eV. The angular momentum of the electron is

The angular momentum of an electron in hydrogen atom is h/pi The kinetic energy of the electron is

The angular momentum of an electron in the hydrogen atom is (2h)/(pi) . What is the potential energy of this electron ?

calculate the angular momentum of the electron in third orbit of hydrogen atom,if the angular momentum in the second orbit of hydrogen atom is L.

The energy of an electron in excited hydrogen atom is -3.4 eV . Then, according to Bohr's therory, the angular momentum of the electron of the electron is

An electron in the ground state of hydrogen has an angular momentum L_(1) and an electron in the fist excited state of lithium has an angular momentum L_(2) . Then,

The angular momentum of the electron in third orbit of hydrogen atom, if the angular momentum in the second orbit of hydrogen is L is

The angular momentum of an electron in hydrogen atom is 4 h// 2 pi . Kinetic energy this electron is