The circle `x^(2)+y^(2)=4` ,cuts the line joining the points `A(1,0),&B(3,4)` in two points P& Q.Let `(BP)/(PA)=alpha>0&(BQ)/(QA)=beta>0` .Then `alpha+beta`

The circle x^(2)+y^(2)=4 cuts the line joining the points A(1,0) and B(3,4) in two points P and Q. Let B(P)/(P)A=alpha and B(Q)/(Q)A=beta. Then alpha and beta are roots of the quadratic equation

If 2x+3y+4=0 is perpendicular bisector of the segment joining the points A(1,2) and B(alpha,beta) then the value of alpha+beta is

If the length of the tangent drawn from (alpha,beta) to the circle x^(2)+y^(2)=6 be twice the length of the tangent from the same point to the circle x^(2)+y^(2)+3x+3y=0, then prove that alpha^(2)+beta^(2)+4 alpha+4 beta+2=0

Let (alpha,beta,gamma) be the mirror image of the point (2,3,5) in the line (x-1)/(2)=(y-2)/(3)=(z-3)/(4) .Then, 2 alpha+3 beta+4 gamma is equal to

The point of intersection of the pair of lines x^(2)+xy+2y^(2)-3x+2y+4=0 is (alpha,beta) then 2 alpha+beta=

A circle x^(2)+y^(2)=a^(2) meets the x-axis at A(-a,0) and B(a,0). P(alpha) and Q( beta ) are two points on the circle so that alpha-beta=2 gamma, where gamma is a constant. Find the locus of the point of intersection of AP and BQ.

The image of the point A(1,2) by the line mirror y=x is the point B and the image of B by the line mirror y=0 is the point (alpha,beta), then a.alpha=1,beta=-2b. alpha=,beta=0calpha=,beta=-1d. none of these

the image of the point A(2,3) by the line mirror y=x is the point B and the image of B by the line mirror y=0 is the point (alpha,beta), find alpha and beta

If the circles described on the line joining the points (0,1) and (alpha,beta) as diameter cuts the X - axis in points whose abscissae are roots of equation x^(2)-5x+3=0 then (alpha,beta)=