If a circle passes through (0,0),(4,0) and touches the circle `x^(2)+y^(2)=36` then the centre of circle

A circle passes through (0,0) and (1,0) and touches the circle x^(2)+y^(2)=9 then the centre of circle is -

The centre of a circle passing through the points (0, 0), (1, 0) and touching the circle x^(2)+y^(2)=9 , is

A circle passes through the points (0,0) and (0,1 ) and also touches the circie x^(2)+y^(2)=16 The radius of the circle is

A circle passes through point (3,sqrt((7)/(2))) and touches the line-pair x^(2)-y^(2)-2x+1=0 Centre of circle lies inside the circle x^(2)+y^(2)-8x+10y+15=0. Coordinates of centre of circle are given by (A) (4,0) (B) (5,0)(C)(6,0)(D)(0,4)

The centre of the circle passing through (0, 0) and (1, 0) and touching the circle x^(2)+y^(2)=9 , is

If a circle C passing through (4,0) touches the circle x^(2)+y^(2)+4x-6y-12=0 externally at a point (1,-1), then the radius of the circle C is :

If a circle C passing through the point (4,0) touches the circle x^(2)+y^(2)+4x-6y=12 externally at the point (1,-1) ,then the radius of C is