A block of mass 5kg is falling downwards in air with an acceleration of 2ms^(-2) air resistance is present. The force applied by block on the earth will be (g=10m/s^(2))

A block of mass 10kg is moving up on an inclined plane with constant acceleration 2 ms^(-2) by applying a constant force F as shown in the figure. (take, g = 10 ms^(-2) ). If the work done on the block by applied force F in 2s is 120x N Joule then the value of N is?

A block of mass 10 kg, moving with acceleration 2m//s^(2) on horizontal rough surface is shown in figure

A block of mass 10 kg is released on rough incline plane. Block start descending with acceleration 2m//s^(2) . Kinetic friction force acting on block is (take g=10m//s^(2) )

The elevator shown in fig. is descending with an acceleration of 2 m//s^(2) . The mass of block A is 0.5 kg. The force exerted by the block A on the block B is

A block of mass 5 kg is placed on bus moving with acceleration 2 m//s^(2) .pseudo force acting on block as seen by a man on ground is -

A body of mass 0.05 kg is observed to fall with an acceleration of 9.5ms^(-2) . The opposing force (in newton) of air on the bod is ( g=9.8ms^(-2) )

The acceleration of block is( g=10 ms-2)

A block of mass 1 kg is at rest relative to a smooth wedge moving leftwards with constant acceleration a = 5 m//s^(-2) .Let N be the normal reation between the block and the wedge . Then (g = 10 m//s^(-2))

The elevator shown in figure is descending with an acceleration of 2m/s^2 . The mass of the block A is 0.5 kg. What force is exerted by the block A on the block B?

A block of mass 1 kg is at rest relative to a smooth wedge leftwards with constant acceleration a =5 m//s^(2) .Let N be the normal reaction between the block and the wedge. Then ( g = 10 m//s^(2) )