In a wheatstone bridge the four arms have each resistance of 50 ohm.The galvanometer current is "

In a Wheatstone's brigde all the four arms have equal resistance R . If the resistance of the galvanometer arm is also R , the equivalent resistance of the combination as seen b the battery is

In a Whatstone's bridge all the four arms have equal resistance R_(0) . If the resistance of the galvanometer arm is 2R_(0) , the equivalent resistance of the combination as seen by the battery is

The firgure shows a circuit diagram of a 'Wheatstone Bridge' to measure the resistance G of the galvanometer The relation (P)/(Q) = (R )/(G) will be satisfied only when

The four arms of a Wheatstone bridge have resistances as shown in the figure. A galvanometer of 15 Omega resistance is connected across BD. Calculate the current through the galvanometer when a potential difference of 10 V is maintained across AC.

Wheaststone bridge is most sensitive when the resistance of all four arms are

Wheatstone bridge is not suitable for the measurement of resistance of the order of

What are the advantages of a Wheatstone bridge method of measuring resistance over other methods ?

In a wheatstone bridge resistance of each of the four sides is 10Omega . If the resistance of the galvanometer is also 10Omega , then effective resistance of the bridge will be

Assertion: When wheatstone bridge is balanced then current through cell depends on resistance of galvanometer. Reason: At balancec condition current through galvanometer is very high.

All the resistance in the given Wheatstone bridge have different values and the current through the galvanometer is zero. The current through the galvanometer will still be zero if,