`(sinB)/(sin(B+C)) = b/a`

In triangleABC, (sinB)/(sin(A+B)) =

In triangleABC, (sinB)/(sin(A+B)) =

Prove that (sin(B-C))/(sinB.sinC) + (sin(C-A))/(sinCsinA) + (sin(A-B))/(sinA.sinB) = 0

In A B C , the median A D divides /_B A C such that /_B A D :/_C A D=2:1 . Then cos(A/3) is equal to (sinB)/(2sinC) (b) (sinC)/(2sinB) (2sinB)/(sinC) (d) none of these

Prove that: (sin(A-C)+2sinA+sin(A+C)) / ("sin"("B"-"C")+2sinB+"sin"(B+C)) = (sinA)/(sinB)

(sin(A-C)+2sinA+sin(A+C))/(sin(B-C)+2sinB+sin(B+C)) is equal to-

(sin(A-C)+2sinA+sin(A+C))/(sin(B-C)+2sinB+sin(B+C)) is equal to

(sin(A-C)+2sinA+sin(A+C))/(sin(B-C)+2sinB+sin(B+C)) is equal to

In any triangle ABC prove that (a^(2)sin(B-C))/(sinA)+(b^(2)sin(C-A))/(sinB)+(c^(2)sin(A-B))/(sinC)=0