When two capacitors are joined in series the resultance capacity is `2.4 muF` and when the same two are joined in parallel the resultant capacity is `10 mu F`. Their individual capacities are.

[" When two capacitors "],[" are joined in series the "],[" resultance capacity is "],[2.4 mu F" and when the "],[" same two are joined in "],[" parallel the resultant "],[" capacity is "10^(mu F)" ."],[" Their individual "],[" capacities are "]

When two capacitors are connected in series, the equivalent capacitance is (15)/(4) muF . When they are connected in parallel, the equivalent capacitance is 16muF . The individual capacitance are

When two capacitors are connected in series, the equivalent capacity is 2 mu F . When they are connected in parallel, the equivalent capacity is 9 microfarad. Find the capacity of the capacitors

When two capacitances are connected in series, the equivalent capacitance is 2.4 mu F and when they connected in parallel, it is 10 mu F . The individual capacitances are

Two capacitors when connected in series the effective capacity is 2muF and when in parallel is 9muF . Calculate the value of each capacitors.

Two capacitors of equal capacities when connected in series have some resultant capacity. Then they are connected in parallel. The resultant capacity of parallel combination is

Three capacitors of 1muF, 2muF and 4muF are joined in series. How many times will the capacity change when they are joined in parallel.

Two capacitors when connected in parallel are equivalent to 6muF and when the same are connected in series then the equivalent becomes 1.5 muF . Calculate the individual capacitances.

Three capacitors of 1 muF, 2 muF and 3 muF are joined in series. How many times will the capacity become when they are joined in parallel ?